ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi Class 22 Review Topics for Test 2 Inhomogeneous linear ordinary differential equations. Method of undetermined coefficients for polynomial, trigonometric, and exponential forcing terms; cases when forcing term satis- fies homogeneous equation. Constant coefficient and Cauchy-Euler problems. Variation of parameters. Reduction of order based on a known solution. Variation of pa- rameters applied to linear systems of ordinary differential equations. Series solutions of linear ordinary differential equations; regular points. Regular singular points; distinct indicial roots; repeated indicial roots; distinct roots differing by an integer. Gamma functions. Bessel Functions. Laplace transforms; definition. Properties; calculation; inverses; convolution theorem. Ap- plication to constant coefficient linear ordinary differential equations; linear integral equa- tions of convolution type. Step function, delta function. Application of Laplace transforms to partial differential equations; diffusion equation. Application of separation of variables to the solution of the diffusion equation. Sturm-Liouville theory; eigenfunction expansions; singular and periodic problems. Review of Fourier series and their properties. References: 2011 Lecture Notes, Professor P. A. Blythe 2021 Lecture Notes, Professor J. W. Jaworski Michael D. Greenberg 1998 Advanced Engineering Mathematics (second edition), Prentice Hall Page 214 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi Sample 1 of Test 2 1. Find the explicit solution of y d2y dx2 = 1 2 [ 1 + ( dy dx )2] that satisfies y = 1, dy dx = 0 at x = 0. Answer: y = 1 + x2 4 2. Given that y = x is a solution of the homogeneous equation x2y′′ − x(x+ 2)y′ + (x+ 2)y = 0, determine the general solution of the inhomogeneous equation x2y′′ − x(x+ 2)y′ + (x+ 2)y = x3ex cosx. Identify a second linearly independent solution of the homogeneous equation. Hint : You are given that ∫ ex sinxdx = 1 2 ex (sinx− cosx) . Answer: second linearly independent solution yh2 = xe x general solution of the inhomogeneous problem y = c1x+ c2xe x + 1 2 xex(sinx− cosx) 3. The equation x2y′′ − (2 + x)xy′ + (2− x)y = 0 possesses series solution of the form y = xr ∑ n=0 anx n (a) Deduce all values of the index r. Answer: r = 1, 2 (b) For the larger of the r values, deduce the general recurrence relation satisfied by the coefficients an, n ≥ 1. Answer: an = n+ 2 n(n+ 1) an−1 (c) Obtain the solution of the recurrence relation corresponding to the larger r value, and give the corresponding solution of the differential equation. Page 215 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi Note: You are required to find only the single solution corresponding to the larger r value. Answer: y1 = x 2 ∑∞ n=0 n+ 2 2n! xn 4. x(t) satisfies the integro-differential equation dx dt + x = 9H(t− 2) + 2 ∫ t 0 e−2τx(t− τ)dτ with x(0) = 3. (a) Let the Laplace transform of x(t) be X(s). Determine X(s). Answer: X(s) = e−2s ( 1 s + 6 s2 − 1 s+ 3 ) + 2 s + 1 s+ 3 (b) Hence find x(t). Answer: x(t) = 2 + e−3t +H(t− 2) (1 + 6(t− 2)− e−3(t−2)) Page 216 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi Sample 2 of Test 2 1. (a) Find both critical points of the system dx dt = −x+ y + y2, dy dt = −x− y. Answer: (x0, y0) = (0, 0), (2,−2) (b) determine the type and stability of each critical point. Answer: (x0, y0) = (0, 0): stable focus, (x0, y0) = (2,−2): unstable saddle 2. (a) You are given that 4x2(1 + x)y′′ − 2xy′ + (2− 3x)y = 0 has solutions of the form y = xr ∑ n=0 anx n. Obtain both possible values of the index r. Answer: r = 1 2 , 1 (b) Using the lower index value, find the general form of the recurrence equation that relates an to an−1. Answer: an = −n− 2 n− 1 2 an−1 (c) Determine the solution for an from the recurrence equation obtained in part (b). Answer: a1 = 2a0, and an = 0 for n ≥ 2 (d) Hence deduce the solution for y(x) that corresponds to the lower of the r values. Note: DO NOT calculate the solution that corresponds to the larger of the r values. Answer: y1(x) = x 1/2(1 + 2x) 3. (a) Determine the general real solution of d2y dx2 + 2 dy dx + λy = 0, (A) where, λ = 1 + µ2. (Your answer should be given in terms of x and µ together with any arbitrary con- stants.) Answer: y(x) = { e−x(A+Bx), µ = 0 e−x(A cosµx+B sinµx), µ ̸= 0 (b) If y(0) = 0, y(1) = 0, Page 217 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi obtain µ and hence the eigenvalues λ. Answer: µ ̸= 0: λ = 1 + n2π2, ϕn(x) = e−x sinnπx for n ≥ 1 (c) Write equation (A) in Sturm-Liouville form and state the weight function w(x). Answer: w(x) = e2x (d) Give the set of eigenfunctions that are orthonormal with respect to the weight func- tion. Hint: ∫ sin2mxdx = 1 2 x− 1 4m cos 2mx. Answer: ϕˆn(x) = √ 2e−x sinnπx 4. (a) Use Fourier tranforms to solve d2y dx2 + 4 dy dx + 4y = 9H(−x)ex given that y → 0 as x→ ±∞. Hint: H(x) represents the step function. Answer: y(x) = (3x+ 1)H(x)e−2x +H(−x)ex (b) Invert the Fourier transform e−3iω.e−ω 2/4. (The inverse required for part (a) and for part (b) can all be obtained from Appendix D in Greenberg.) Answer: 1√ π e−(x−3) 2 Page 218 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi Sample 3 of Test 2 1. (25 points) (a) Find the solution of y d2y dx2 = dy dx − ( dy dx )2 that satisfies y = 1, dy dx = 2, at x = 0. Answer: y + ln 2 1 + y = x+ 1 (b) What solution satisfies y = 1, dy dx = 0, at x = 0. Answer: y(x) = 1 2. (30 points) (a) Find the general solution of the homogeneous equation x2 d2y dx2 − 2xdy dx + 2y = 0 by first converting it to a constant coefficient differential equation. Answer: yh(x) = c1x+ c2x 2 (b) Use the method of undetermined coefficients to obtain the general solution of x2 d2y dx2 − 2xdy dx + 2y = x. Answer: y(x) = c1x+ c2x 2 − x lnx 3. (25 points) (a) Given that 2x2y′′ + (3x− 6x2)y′ − (1 + 3x)y = 0 has solutions of the form y = xr ∑ n=0 anx n determine both possible values of the index r. Answer: r = −1, 1 2 Page 219 ENGR452/BIOE452/CHE452/ME452 Instructor: Parisa Khodabakhshi (b) For the lower index value, find a recurrence equation relating an to an−1. Answer: an = 3 n an−1 (c) Obtain the solution of the recurrence equation for an. Answer: an = 3n n! a0 (d) Write down the solutions for y(x) that corresponds to the lower of the r values. If possible express your final answer in terms of a simple elementary function of x. Note: DO NOT calculate the solution that corresponds to the larger r value. Answer: y(x) = x−1 ∑∞ n=0 3n n! xn = x−1e3x 4. (20 points) Use the results in Appendix C of Greenberg to invert the Laplace transform ln s s(s+ 1) Part of your answer should be expressed in terms of the functions ϕ(t) = ∫ t 0 eτ (− ln τ)dτ . Answer: e−tϕ(t)− γ(1− e−t) Page 220
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