# 程序代写案例-CC0929

CC0929 Semester 2, 2017 Page 1 of 3
PHYS1003 Physics 1 (Technological) Formula Sheet
Fluids
ρ =
m
V
p =
F
A
p =
nRT
V
=
NkT
V
pgauge = p− p0
Q =
dV
dt
= Av A1v1 = A2v2
p1 + ρgy1 +
1
2
ρv21 = p2 + ρgy2 +
1
2
ρv22 F =
ηAv
L
Q =
dV
dt
=
pi∆pR4
8ηL
Re =
ρvL
η
FD = 6piηrv FD =
1
2
ρACDv
2
Quantum Physics
E = hf hf = Kmax + Φ
p =
hf
c
=
h
λ
L =

l(l + 1)~
∆λ =
h
mc
(1− cosφ) S =

3
4
~
λ =
h
p
=
h
mv
~ =
h
2pi
− ~
2
2m
d2ψ
dx2
+ Uψ = Eψ λ =
2L
n
for n = 1, 2, 3 . . .
∆x∆px ≥ ~/2, ∆y∆py ≥ ~/2, ∆z∆pz ≥ ~/2
+∞∫
−∞
|ψ(x)|2dx = 1
En =
(
h2
8mL2
)
n2 for n = 1, 2, 3 . . . hf =
hc
λ
= Ei − Ef
ψn(x) = A sin
(npi
L
x
)
for n = 1, 2, 3 . . .
1
λ
= RH
(
1
n2lower
− 1
n2upper
)
En = − me
4
8ε02h2n2
= −13.60
n2
eV for n = 1, 2, 3 . . . λmT = 2.90× 10−3 m.K
k =

2m(U0 − E)
~
U = −→µ · −→B
sin θ =

2d
1
CC0929 Semester 2, 2017 Page 2 of 3
Electricity & Magnetism/Circuits
F =
|q1q2|
4piε0r2
−→
F = q(
−→
E +−→v ×−→B )
−→
E =
−→
F
q0
ΦB =

B cosφdA =
∫ −→
B · d−→A
ΦE =

E cos θdA =
∫ −→
E · d−→A
∮ −→
B · d−→A = 0∮ −→
E · d−→A = Qencl
ε0
R =
mv
|q|B
V =
U
q
−→
F = i
−→
l ×−→B
V =
1
4piε0

i
qi
ri
Va − Vb =
b∫
a
−→
E · d−→l
C =
Q
Vab
= ε0
A
d
(parallel plates) B =
µ0I
2pir
(straight wire)
U =
Q2
2C
=
1
2
CV 2 =
1
2
QV
F
L
=
µ0II

2pir
K =
C
C0
E =
E0
K
I =
dQ
dt
∮ −→
B · d−→l = µ0Iencl
−→
J = nq−→vd B = µ0NI
L
(solenoid)
ρ =
E
J
ε = −N dΦB
dt
R =
ρL
A
ε = vBL
P = V I = I2R =
V 2
R
∮ −→
E · d−→l = −dΦB
dt
ε = −Ldi
dt
L =
NΦB
i
U =
1
2
LI2 VR = IR, VL = IXL, VC = IXC
q = Cε
(
1− e−t/RC
)
q = Q0e−t/RC
ω =
1√
LC
τ = RC
2
CC0929 Semester 2, 2017 Page 3 of 3
Electricity & Magnetism/Circuits (continued)
τ =
L
R
Rtotal = R1 +R2
vout =
vinR2
R1 +R2
1
Rtotal
=
1
R1
+
1
R2
v = V0ejωt = V0 cos (ωt) + jV0 sin (ωt) XC =
1
ωC
v = Zi XL = ωL
Q =
f0
f2 − f1 Ztotal = Z1 + Z2
vout =
vinZ2
Z1 + Z2
1
Ztotal
=
1
Z1
+
1
Z2
ω = 2pif
F = ma (vx)f = (vx)i + ax∆t
xf = xi + (vx)i∆t+
1
2
ax(∆t)2 (vx)2f = (vx)
2
i + 2ax∆x
3

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