辅导案例-MEC4428

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MONASH UNIVERSITY
Department of Mechanical and Aerospace Engineering
MEC4428 — Advanced Dynamics —
Assignment 2: Rigid Body Dynamics — The Motion of a Com-
pound Pendulum due: Thursday 10am - 17th October 2018, assignment box building
31
A correct worked derivation of the governing equations with accompanying extracts of the function
file, and the commands to solve for and plot the solutions will earn 4 marks contributing to your
final score.
A Compound Pendulum
Write a MATLAB code to determine the motion of the two component pendulum shown in the
figure below. The two parts are both rigid bodies, connected by a pivot at point D. The first link
is pinned at the point O. Specifically:
1. plot the trajectory of point C, the centre of the square,
2. plot the phase portraits (θ˙ versus θ and φ˙ versus φ),
3. plot the total energy - this should be a constant as there is no dissipation,
4. finally, determine the approximate governing equations for small angles (i.e.,
θ → 0, φ → pi). Compare the solution from the original set of equations with the
approximate set for initial conditions θ(0) = pi/12, φ(0) = pi − pi/12, θ˙(0) = φ˙(0) = 0.
You have choice of how to derive the equations. You can use Angular Momentum Balance
for the disk about the point D and for the whole system about O. You could also substitute one
of these equations with total energy conservation for the two masses. It is also possible to use
either virtual work or the Lagrange equations. In any case you should get a system of 4 first-order
differential equations for θ˙, θ¨, φ˙, φ¨, which will then be solved using your favourite MATLAB ODE
solver (typically ODE45). Assume the following parameters and initial conditions. I have put
up some MATLAB code for a double pendulum (two rods) that you might like to modify for the
current problem.
• m1 = m2 = m = 1
• L = 2, H = 1 (IS = mH2/6; IR = mL2/12)
• d = 1/6 (the length CD)
• g = 1 (Note this is not a mistake - the problem has been non-dimensionalised...)
• θ(0) = pi/2, φ(0) = pi/2
• θ˙(0) = φ˙(0) = 0
1
HR
m, R, IS
O
C
G
θ
φ
D
m, L, I
2
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